Design and implement a lexical analyzer for given language using C and the lexical analyzer should ignore redundant spaces, tabs, and new lines.

Design and implement  a lexical analyzer for given language using  C and the lexical analyzer should ignore redundant spaces, tabs, and new lines -

Program-

#include <string.h>

#include <ctype.h>

#include <stdio.h>

void keyword(char str[10])

{

if (strcmp("for", str) == 0 || strcmp("while", str) == 0 || strcmp("do", str) == 0 || strcmp("int", str) == 0 || strcmp("float", str) == 0 || strcmp("char", str) == 0 || strcmp("double", str) == 0 ||

strcmp("static", str) == 0 || strcmp("switch", str) == 0 || strcmp("case", str) == 0)

printf("\n%s is a keyword", str);

else

printf("\n%s is an identifier", str);

}

main()

{

FILE *f1, *f2, *f3;

char c, str[10], st1[10];

int num[100], lineno = 0, tokenvalue = 0, i = 0, j = 0, k = 0;

printf("\nEnter the c program"); /*gets(st1); */

f1 = fopen("input", "w");

while ((c = getchar()) != EOF)

putc(c, f1);

fclose(f1);

f1 = fopen("input", "r");

f2 = fopen("identifier", "w");

f3 = fopen("specialchar", "w");

while ((c = getc(f1)) != EOF)

{

if (isdigit(c))

{

tokenvalue = c - '0';

c = getc(f1);

while (isdigit(c))

{

tokenvalue *= 10 + c - '0';

c = getc(f1);

}

num[i++] = tokenvalue;

ungetc(c, f1);

}

else if (isalpha(c))

{

putc(c, f2);

c = getc(f1);

while (isdigit(c) || isalpha(c) || c == '_' || c == '$')

{

putc(c, f2);

c = getc(f1);

}

putc(' ', f2);

ungetc(c, f1);

}

else if (c == ' ' || c == '\t')

printf(" ");

else

if (c == '\n')

lineno++;

else

putc(c, f3);

}

fclose(f2);

fclose(f3);

fclose(f1);

printf("\nThe no's in the program are");

for (j = 0; j < i; j++)

printf("%d", num[j]);

printf("\n");

f2 = fopen("identifier", "r");

k = 0;

printf("The keywords and identifiersare:");

while ((c = getc(f2)) != EOF)

{

if (c != ' ')

str[k++] = c;

else

{

str[k] = '\0';

keyword(str);

k = 0;

}

}

fclose(f2);

f3 = fopen("specialchar", "r");

printf("\nSpecial characters are");

while ((c = getc(f3)) != EOF)

printf("%c", c);

printf("\n");

fclose(f3);

printf("Total no. of lines are:%d", lineno);

}

Input:

Enter Program $

for termination:

{

int a[3], t1, t2;

t1 = 2;a[0] = 1;a[1] = 2;a[t1] = 3;

t2 = -(a[2] + t1 *6) / (a[2] - t1);

if t2 > 5 then

print(t2);

else

{

int t3;

t3 = 99;

t2 = -25;

print(-t1 + t2 *t3); /*this is a comment on 2 lines */

}

endif

}

(cntrl + z)